What is derivative of f(x)=e^{tan(θ)} ?

The answer to derivative of f(x)=e^{tan(θ)} is derivative of θ=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of f(x)=e^{tan(θ)}

derivative of

f (x) = e^{t a n (θ)}

\frac{d}{d x} (θ) = 0

Solution steps

f (x) = e^{t a n (θ)}

Treat

θ

θ (x)

Differentiate both sides:

0 = e^{t a n (θ)} sec^{2} (θ) \frac{d}{d x} (θ)

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = 0

\frac{d}{d x} (θ) = 0

\frac{d y}{d θ} = sin (θ)

\int x e^{x y} + 2 x y + \frac{1}{x}

x \to - 2 lim (\frac{( x - 2 )}{x + 2})

\int_{- 3}^{5} (1 + 4 x) d x

\int sin (x) sin (x) d x

What is derivative of f(x)=e^{tan(θ)} ?
The answer to derivative of f(x)=e^{tan(θ)} is derivative of θ=0