What is the derivative of f(x)2z(9z^2-3z+1)^4 ?

The derivative of f(x)2z(9z^2-3z+1)^4 is 2xz(9z^2-3z+1)^4

What is the first derivative of f(x)2z(9z^2-3z+1)^4 ?

The first derivative of f(x)2z(9z^2-3z+1)^4 is 2xz(9z^2-3z+1)^4

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derivative of

f (x) 2 z (9 z^{2} - 3 z + 1)^{4}

2 x z (9 z^{2} - 3 z + 1)^{4}

Solution steps

\frac{d}{df} (f x \cdot 2 z (9 z^{2} - 3 z + 1)^{4})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \cdot 2 z (9 z^{2} - 3 z + 1)^{4} \frac{df}{df}

Apply the common derivative:

\frac{df}{df} = 1

= x \cdot 2 z (9 z^{2} - 3 z + 1)^{4} \cdot 1

Simplify

= 2 x z (9 z^{2} - 3 z + 1)^{4}

\int_{\frac{π}{6}}^{π} sin (θ) d θ

\int \frac{8}{cos ( x ) - 1} d x

y = x^{3}, x = - 2, x = 2

x \to 3 lim (\frac{x ^{2} + 4}{x - 5})

13 x

What is the derivative of f(x)2z(9z^2-3z+1)^4 ?
The derivative of f(x)2z(9z^2-3z+1)^4 is 2xz(9z^2-3z+1)^4
What is the first derivative of f(x)2z(9z^2-3z+1)^4 ?
The first derivative of f(x)2z(9z^2-3z+1)^4 is 2xz(9z^2-3z+1)^4