What is the integral from 6 to 7 of 1/20+x/(40) ?

The integral from 6 to 7 of 1/20+x/(40) is 17/80

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integral from 6 to 7 of 1/20+x/(40)

\int_{6}^{7} \frac{1}{20} + \frac{x}{40} d x

\frac{17}{80}

Decimal Notation

0.2125

Solution steps

\int_{6}^{7} \frac{1}{20} + \frac{x}{40} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{6}^{7} \frac{1}{20} d x + \int_{6}^{7} \frac{x}{40} d x

\int_{6}^{7} \frac{1}{20} d x = \frac{1}{20}

\int_{6}^{7} \frac{x}{40} d x = \frac{13}{80}

= \frac{1}{20} + \frac{13}{80}

Simplify

\frac{1}{20} + \frac{13}{80} : \frac{17}{80}

= \frac{17}{80}

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What is the integral from 6 to 7 of 1/20+x/(40) ?
The integral from 6 to 7 of 1/20+x/(40) is 17/80