What is the derivative of (ln(x)/(5x^3)) ?

The derivative of (ln(x)/(5x^3)) is (1-3ln(x))/(5x^4)

What is the first derivative of (ln(x)/(5x^3)) ?

The first derivative of (ln(x)/(5x^3)) is (1-3ln(x))/(5x^4)

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\frac{d}{d x} (\frac{ln ( x )}{5 x ^{3}})

\frac{1 - 3 ln ( x )}{5 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{ln ( x )}{5 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (\frac{ln ( x )}{x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{5} \cdot \frac{\frac{d}{d x} ( ln ( x ) ) x ^{3} - \frac{d}{d x} ( x ^{3} ) ln ( x )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{1}{5} \cdot \frac{\frac{1}{x} x ^{3} - 3 x ^{2} ln ( x )}{( x ^{3} ) ^{2}}

Simplify

\frac{1}{5} \cdot \frac{\frac{1}{x} x ^{3} - 3 x ^{2} ln ( x )}{( x ^{3} ) ^{2}} : \frac{1 - 3 ln ( x )}{5 x ^{4}}

= \frac{1 - 3 ln ( x )}{5 x ^{4}}

\int 7 x sec^{2} (x) d x

10000 - 9000 e^{- 0.3 t}

\frac{s}{( s - 1 ) ^{2}}

y = 2 x^{\frac{3}{2}}

\frac{\partial}{\partial x} (x^{2} y^{3} - 4 y)

What is the derivative of (ln(x)/(5x^3)) ?
The derivative of (ln(x)/(5x^3)) is (1-3ln(x))/(5x^4)
What is the first derivative of (ln(x)/(5x^3)) ?
The first derivative of (ln(x)/(5x^3)) is (1-3ln(x))/(5x^4)