What is the solution for y^'=(5x^2+y^2)/(xy) ?

The solution for y^'=(5x^2+y^2)/(xy) is y=xsqrt(10ln(x)+c_{1)},y=-xsqrt(10ln(x)+c_{1)}

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y^'=(5x^2+y^2)/(xy)

y^{^{'}} = \frac{5 x ^{2} + y ^{2}}{x y}

y = x 10 ln (x) + c_{1}, y = - x 10 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{5 x ^{2} + y ^{2}}{x y}

Solve Bernoulli ODE:

y = x 10 ln (x) + c_{1}, y = - x 10 ln (x) + c_{1}

y = x 10 ln (x) + c_{1}, y = - x 10 ln (x) + c_{1}

\int_{1}^{2} t^{2} t^{3} + 1 d t

\int csc^{4} (3 - 2 x) d x

\int e^{4 x} (4) d x

\frac{4}{s ^{2} + 2 s + 2}

\int (3 x^{2} - 5 x + 2) d x

What is the solution for y^'=(5x^2+y^2)/(xy) ?
The solution for y^'=(5x^2+y^2)/(xy) is y=xsqrt(10ln(x)+c_{1)},y=-xsqrt(10ln(x)+c_{1)}