What is the d/(d{x)}(sqrt({x)+{y}{z}}) ?

The d/(d{x)}(sqrt({x)+{y}{z}}) is 1/(2sqrt({x)+{y){z}}}

What is the first d/(d{x)}(sqrt({x)+{y}{z}}) ?

The first d/(d{x)}(sqrt({x)+{y}{z}}) is 1/(2sqrt({x)+{y){z}}}

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\frac{d}{d x} (x + y z)

\frac{1}{2 x + y z}

Solution steps

\frac{d}{d x} (x + y z)

Apply the chain rule:

\frac{1}{2 x + y z} \frac{d}{d x} (x + y z)

= \frac{1}{2 x + y z} \frac{d}{d x} (x + y z)

\frac{d}{d x} (x + y z) = 1

= \frac{1}{2 x + y z} \cdot 1

Simplify

= \frac{1}{2 x + y z}

1.5 - 1.5 e^{- t}

\int sec (4 x) tan^{5} (4 x) d x

(1 + x^{2}) \frac{d y}{d x} = (1 + y)^{2}

\int (x^{3} + x^{2})^{12} (3 x^{2} + 2 x) d x

What is the d/(d{x)}(sqrt({x)+{y}{z}}) ?
The d/(d{x)}(sqrt({x)+{y}{z}}) is 1/(2sqrt({x)+{y){z}}}
What is the first d/(d{x)}(sqrt({x)+{y}{z}}) ?
The first d/(d{x)}(sqrt({x)+{y}{z}}) is 1/(2sqrt({x)+{y){z}}}