What is the limit as x approaches infinity of (-2)^x ?

The limit as x approaches infinity of (-2)^x is diverges

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limit as x approaches infinity of (-2)^x

x \to \infty lim ((- 2)^{x})

diverges

Solution steps

x \to \infty lim ((- 2)^{x})

Apply exponent rule:

(a \cdot b)^{n} = a^{n} \cdot b^{n}

(- 2)^{x} = (- 1)^{x} (2)^{x}

= x \to \infty lim ((- 1)^{x} \cdot 2^{x})

Apply Limit Divergence Criterion:

diverges

= diverges

\frac{\partial}{\partial x} (2 π x y + π x^{2})

\frac{\partial}{\partial x} (e^{- 3 x})

cos (y) + (1 + e^{- x}) sin (y) \frac{d y}{d x} = 0

\int \frac{1}{5 x + 4} d x

x \to 0 lim (\frac{cos ( 4 x ) - cos ( 2 x )}{x ^{2}})

What is the limit as x approaches infinity of (-2)^x ?
The limit as x approaches infinity of (-2)^x is diverges