What is the tangent of f(x)=x^2-7x+7,(0,7) ?

The tangent of f(x)=x^2-7x+7,(0,7) is y=-7x+7

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tangent of f(x)=x^2-7x+7,(0,7)

tangent of

f (x) = x^{2} - 7 x + 7, (0, 7)

y = - 7 x + 7

Solution steps

Find the slope of

f (x) = x^{2} - 7 x + 7 : \frac{df ( x )}{d x} = 2 x - 7

Compute the slope of

f (x) = x^{2} - 7 x + 7

(0, 7) : m = - 7

Find the line with slope m=

- 7

and passing through

(0, 7) : y = - 7 x + 7

y = - 7 x + 7

x \to 1 + lim (4 x - 2 x^{2})

\frac{x}{x + e ^{(x^{2})}}

y = (5 x + 14)^{5}

(2 + y) d x - 3 (3 - x) d y = 0

\int 18 (200 + t)^{2} d t

What is the tangent of f(x)=x^2-7x+7,(0,7) ?
The tangent of f(x)=x^2-7x+7,(0,7) is y=-7x+7