What is laplacetransform e^{1-2t} ?

The answer to laplacetransform e^{1-2t} is e/(s+2)

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laplacetransform e^{1-2t}

laplace transform

e^{1 - 2 t}

\frac{e}{s + 2}

Solution steps

L {e^{1 - 2 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{1} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{1} \frac{1}{s + 2}

Refine

e^{1} \frac{1}{s + 2} : \frac{e}{s + 2}

= \frac{e}{s + 2}

\frac{d}{d x} (\frac{2 x ^{3} - 6 π ^{2}}{x ^{5}})

\int π cos (\frac{n x}{2}) d x

x \to 0 lim (- 7)

\frac{\partial}{\partial x} (e^{- x} cos (π t))

\int \frac{x ^{2} - 1}{x ^{2}} d x

What is laplacetransform e^{1-2t} ?
The answer to laplacetransform e^{1-2t} is e/(s+2)