What is the derivative of (x^4+x^2+1^4) ?

The derivative of (x^4+x^2+1^4) is 4(x^4+x^2+1)^3(4x^3+2x)

What is the first derivative of (x^4+x^2+1^4) ?

The first derivative of (x^4+x^2+1^4) is 4(x^4+x^2+1)^3(4x^3+2x)

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\frac{d}{d x} ((x^{4} + x^{2} + 1)^{4})

4 (x^{4} + x^{2} + 1)^{3} (4 x^{3} + 2 x)

Solution steps

\frac{d}{d x} ((x^{4} + x^{2} + 1)^{4})

Apply the chain rule:

4 (x^{4} + x^{2} + 1)^{3} \frac{d}{d x} (x^{4} + x^{2} + 1)

= 4 (x^{4} + x^{2} + 1)^{3} \frac{d}{d x} (x^{4} + x^{2} + 1)

\frac{d}{d x} (x^{4} + x^{2} + 1) = 4 x^{3} + 2 x

= 4 (x^{4} + x^{2} + 1)^{3} (4 x^{3} + 2 x)

y = lo g_{2} (4 - 9 x)

\frac{2 x}{x ^{2} + 1}

\int x^{5} 1 + x^{6} d x

x \to - 1 + lim (\frac{x}{1 - x ^{4}})

\frac{\partial}{\partial x} (x^{0.75} y^{0.25})

What is the derivative of (x^4+x^2+1^4) ?
The derivative of (x^4+x^2+1^4) is 4(x^4+x^2+1)^3(4x^3+2x)
What is the first derivative of (x^4+x^2+1^4) ?
The first derivative of (x^4+x^2+1^4) is 4(x^4+x^2+1)^3(4x^3+2x)