What is the slope of f(x)= 3/(1+x^2) ?

The slope of f(x)= 3/(1+x^2) is -(6x)/((1+x^2)^2)

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slope of f(x)= 3/(1+x^2)

slope

f (x) = \frac{3}{1 + x ^{2}}

- \frac{6 x}{( 1 + x ^{2} ) ^{2}}

Solution steps

f (x) = \frac{3}{1 + x ^{2}}

In order to find the slope of the function, take the derivative of

\frac{3}{1 + x ^{2}}

\frac{d}{d x} (\frac{3}{1 + x ^{2}}) = - \frac{6 x}{( 1 + x ^{2} ) ^{2}}

- \frac{6 x}{( 1 + x ^{2} ) ^{2}}

(7^{x})^{^{'}}

\frac{d y}{d x} = \frac{sin ( x )}{e ^{y}}

\int_{0}^{π} 11 sin^{2} (4 x) d x

2 t^{2} - 2 t - 2

\frac{\partial}{\partial x} (- 6 e^{x} ln (y))

What is the slope of f(x)= 3/(1+x^2) ?
The slope of f(x)= 3/(1+x^2) is -(6x)/((1+x^2)^2)