What is the solution for (e^x+2xy^2)dx+2x^2ydy=0 ?

The solution for (e^x+2xy^2)dx+2x^2ydy=0 is y=(sqrt(-e^x+c_{1)})/x ,y=-(sqrt(-e^x+c_{1)})/x

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(e^x+2xy^2)dx+2x^2ydy=0

(e^{x} + 2 x y^{2}) d x + 2 x^{2} y d y = 0

y = \frac{- e ^{x} + c _{1}}{x}, y = - \frac{- e ^{x} + c _{1}}{x}

Solution steps

(e^{x} + 2 x y^{2}) d x + 2 x^{2} y d y = 0

Solve Bernoulli ODE:

y = \frac{- e ^{x} + c _{1}}{x}, y = - \frac{- e ^{x} + c _{1}}{x}

y = \frac{- e ^{x} + c _{1}}{x}, y = - \frac{- e ^{x} + c _{1}}{x}

\int 3 x 3 x^{2} + 4 d x

\int \frac{( 2 x )}{( x - 2 ) ( x + 1 )} d x

\frac{\partial}{\partial x} (x \cdot e^{x^{2} - 4})

\frac{d}{d x} ((ln (6 x))^{2})

\frac{d}{d x} (- \frac{x ^{2}}{x + 1})

What is the solution for (e^x+2xy^2)dx+2x^2ydy=0 ?
The solution for (e^x+2xy^2)dx+2x^2ydy=0 is y=(sqrt(-e^x+c_{1)})/x ,y=-(sqrt(-e^x+c_{1)})/x