What is the tangent of f(x)=9-2x^2,(2,1) ?

The tangent of f(x)=9-2x^2,(2,1) is y=-8x+17

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tangent of f(x)=9-2x^2,(2,1)

tangent of

f (x) = 9 - 2 x^{2}, (2, 1)

y = - 8 x + 17

Solution steps

Find the slope of

f (x) = 9 - 2 x^{2} : \frac{df ( x )}{d x} = - 4 x

Compute the slope of

f (x) = 9 - 2 x^{2}

(2, 1) : m = - 8

Find the line with slope m=

- 8

and passing through

(2, 1) : y = - 8 x + 17

y = - 8 x + 17

x \to - 5 lim (\frac{x ^{2} + 3 x - 10}{2 x ^{2} + 15 x + 25})

\int 8 sin^{3} (x) cos^{2} (x) d x

f (x) = (1 + x + x^{2})^{99}

f (x) = \frac{1}{5 + 3 x}, (2, \frac{1}{11})

\int_{1}^{2} 8 r^{2} ln (r) d r

What is the tangent of f(x)=9-2x^2,(2,1) ?
The tangent of f(x)=9-2x^2,(2,1) is y=-8x+17