What is the derivative of f(x)=((2x)/7+1) ?

The derivative of f(x)=((2x)/7+1) is 2/7

What is the first derivative of f(x)=((2x)/7+1) ?

The first derivative of f(x)=((2x)/7+1) is 2/7

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derivative of

f (x) = (\frac{2 x}{7} + 1)

\frac{2}{7}

Solution steps

\frac{d}{d x} ((\frac{2 x}{7} + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2 x}{7}) + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{2 x}{7}) = \frac{2}{7}

\frac{d}{d x} (1) = 0

= \frac{2}{7} + 0

Simplify

= \frac{2}{7}

\int x^{2} sin^{2} (x) d x

x \to 2 - lim (x + 1)

arccot (u)

5 \cdot y^{^{''}} - 4 y^{^{'}} = 0

f (x) = 27000 (1 + \frac{0.0375}{4})^{3}

What is the derivative of f(x)=((2x)/7+1) ?
The derivative of f(x)=((2x)/7+1) is 2/7
What is the first derivative of f(x)=((2x)/7+1) ?
The first derivative of f(x)=((2x)/7+1) is 2/7