What is (\partial)/(\partial x)(2x-1) ?

The answer to (\partial)/(\partial x)(2x-1) is 2

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(\partial)/(\partial x)(2x-1)

\frac{\partial}{\partial x} (2 x - 1)

2

Solution steps

\frac{\partial}{\partial x} (2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (1) = 0

= 2 - 0

Simplify

= 2

\int x y + 1 d y

\frac{1}{( t + 1 ) ^{2}}

\int \frac{x + 4}{2 x + 3} d x

y^{^{''}} + y = e^{x} sin (x)

\int \frac{2 x}{x} d x

What is (\partial)/(\partial x)(2x-1) ?
The answer to (\partial)/(\partial x)(2x-1) is 2