What is the integral of 1/((1+x^2)) ?

The integral of 1/((1+x^2)) is arctan(x)+C

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integral of 1/((1+x^2))

\int \frac{1}{( 1 + x ^{2} )} d x

arctan (x) + C

Solution steps

\int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

1 2^{9 x}

x \to 2 lim (\frac{x - 2}{∣ x - 2 ∣})

\int sin (2 x) e^{(3 x)} d x

y \to 0 lim (\frac{0}{y ^{2}})

\frac{1}{( s + 1 ) ( s + 3 ) ^{2}}

What is the integral of 1/((1+x^2)) ?
The integral of 1/((1+x^2)) is arctan(x)+C