What is the integral from 0 to 3 of xe^{-x} ?

The integral from 0 to 3 of xe^{-x} is -4/(e^3)+1

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integral from 0 to 3 of xe^{-x}

\int_{0}^{3} x e^{- x} d x

- \frac{4}{e ^{3}} + 1

Decimal Notation

0.80085 \dots

Solution steps

\int_{0}^{3} x e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{0}^{3}

= [- e^{- x} x - \int - e^{- x} d x]_{0}^{3}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{0}^{3}

Compute the boundaries:

- \frac{4}{e ^{3}} + 1

= - \frac{4}{e ^{3}} + 1

\frac{A}{y ^{12}} + B e^{y}

f (x) = x^{2} - 6, (3, 3)

\frac{d}{d x} (x ln (x^{2} + 1))

\int \frac{e ^{x}}{( 1 + e ^{x} )} d x

\int (3 + x) d x

What is the integral from 0 to 3 of xe^{-x} ?
The integral from 0 to 3 of xe^{-x} is -4/(e^3)+1