What is the derivative of g(x)=-x^2+7x+7 ?

The derivative of g(x)=-x^2+7x+7 is -2x+7

What is the first derivative of g(x)=-x^2+7x+7 ?

The first derivative of g(x)=-x^2+7x+7 is -2x+7

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derivative of

g (x) = - x^{2} + 7 x + 7

- 2 x + 7

Solution steps

\frac{d}{d x} (- x^{2} + 7 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (7 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (7) = 0

= - 2 x + 7 + 0

Simplify

= - 2 x + 7

y^{^{''}} + 16 y^{^{'}} + 65 y = 0, y (0) = 1, y^{^{'}} (0) = 0

f (x) = 8 x^{\frac{1}{3}} - 5, at x = 8

3 y y^{^{'}} = x

\frac{d}{d t} (2^{t} - 2 t)

\frac{d}{d y} (x + 2 y)

What is the derivative of g(x)=-x^2+7x+7 ?
The derivative of g(x)=-x^2+7x+7 is -2x+7
What is the first derivative of g(x)=-x^2+7x+7 ?
The first derivative of g(x)=-x^2+7x+7 is -2x+7