What is the derivative of (-x^2)/(y^2) ?

The derivative of (-x^2)/(y^2) is -(2x)/(y^2)

What is the first derivative of (-x^2)/(y^2) ?

The first derivative of (-x^2)/(y^2) is -(2x)/(y^2)

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derivative of

\frac{- x ^{2}}{y ^{2}}

- \frac{2 x}{y ^{2}}

Solution steps

\frac{d}{d x} (\frac{- x ^{2}}{y ^{2}})

Simplify

\frac{- x ^{2}}{y ^{2}} : - \frac{x ^{2}}{y ^{2}}

= \frac{d}{d x} (- \frac{x ^{2}}{y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{y ^{2}} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{y ^{2}} \cdot 2 x^{2 - 1}

Simplify

- \frac{1}{y ^{2}} \cdot 2 x^{2 - 1} : - \frac{2 x}{y ^{2}}

= - \frac{2 x}{y ^{2}}

- 4 x^{2}

y^{^{'}} = \frac{3 y - 4 x}{2 y - 3 x}

\int x y d y

y = 3 x, x + y = 4, y = 1, y = 0

\int \frac{3}{x ^{2} + 3} d x

What is the derivative of (-x^2)/(y^2) ?
The derivative of (-x^2)/(y^2) is -(2x)/(y^2)
What is the first derivative of (-x^2)/(y^2) ?
The first derivative of (-x^2)/(y^2) is -(2x)/(y^2)