What is (\partial)/(\partial y)(cos(x)cos(y)) ?

The answer to (\partial)/(\partial y)(cos(x)cos(y)) is -cos(x)sin(y)

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(\partial)/(\partial y)(cos(x)cos(y))

\frac{\partial}{\partial y} (cos (x) cos (y))

- cos (x) sin (y)

Solution steps

\frac{\partial}{\partial y} (cos (x) cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (x) \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= cos (x) (- sin (y))

Simplify

= - cos (x) sin (y)

\int e^{4 x + 8} d x

f (x) = \frac{2 x + 1}{x - 1}

\frac{d}{d x} (\frac{\frac{d}{d x} ( ln ( x ) )}{x})

x^{2}, 8 + x

What is (\partial)/(\partial y)(cos(x)cos(y)) ?
The answer to (\partial)/(\partial y)(cos(x)cos(y)) is -cos(x)sin(y)