What is the limit as x approaches-5+of sqrt(25-x^2) ?

The limit as x approaches-5+of sqrt(25-x^2) is 0

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limit as x approaches-5+of sqrt(25-x^2)

x \to - 5 + lim (25 - x^{2})

0

Solution steps

x \to - 5 + lim (25 - x^{2})

Plug in the value

x = - 5

= 25 - (- 5)^{2}

Simplify

25 - (- 5)^{2} : 0

= 0

y^{^{''}} + y = cos (3 t), y (0) = 1, y^{^{'}} (0) = 0

f (x) = 8 x

x^{4} - 13 x^{2} + 36

\frac{d}{d x} (\frac{2 x ^{2}}{6 x + 1})

x \to \infty lim (\frac{x ^{2} + 2 ^{x}}{( x + 1 ) ^{2} + 2 ^{x + 1}})

What is the limit as x approaches-5+of sqrt(25-x^2) ?
The limit as x approaches-5+of sqrt(25-x^2) is 0