What is the limit as x approaches 0 of-1/1+1/x ?

The limit as x approaches 0 of-1/1+1/x is diverges

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limit as x approaches 0 of-1/1+1/x

x \to 0 lim (- \frac{1}{1} + \frac{1}{x})

diverges

Solution steps

x \to 0 lim (- \frac{1}{1} + \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (- \frac{1}{1} + \frac{1}{x}) = \infty

x \to 0 - lim (- \frac{1}{1} + \frac{1}{x}) = - \infty

= diverges

arccos (x^{2} + \frac{3}{2} x)

\frac{d}{d x} (e^{- 8 x} cos (8 x))

n = 0 \sum \infty e^{- n - 1}

\frac{\partial}{\partial y} (8 x^{2} + 7 y^{2} + 2)

\frac{d}{d x} (x (4^{- 2 x}))

What is the limit as x approaches 0 of-1/1+1/x ?
The limit as x approaches 0 of-1/1+1/x is diverges