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Popular >

y^'=xy+x-2y-2

Solution

y^{^{'}} = x y + x - 2 y - 2

Solution

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} - 1

Solution steps

y^{'} (x) = x y + x - 2 y - 2

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} - 1

Popular Examples

sum from n=2 to infinity of ln(1-1/(n^2))

n = 2 \sum \infty ln (1 - \frac{1}{n ^{2}})

tangent of y=(x^2)/(x-8),(2, 2/5)tangent of

y = \frac{x ^{2}}{x - 8}, (2, \frac{2}{5})

integral of sin(e^{2x})

\int sin (e^{2 x}) d x

derivative of (5x)/(x-2)derivative of

\frac{5 x}{x - 2}

tangent of f(x)=6x^2-3,\at x=-9 tangent of

f (x) = 6 x^{2} - 3, at x = - 9

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy+x-2y-2 ?
The solution for y^'=xy+x-2y-2 is y=e^{(x^2)/2-2x+c_{1}}-1