What is the derivative of 3x^2+6x ?

The derivative of 3x^2+6x is 6x+6

What is the first derivative of 3x^2+6x ?

The first derivative of 3x^2+6x is 6x+6

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\frac{d}{d x} (3 x^{2} + 6 x)

6 x + 6

Solution steps

\frac{d}{d x} (3 x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

= 6 x + 6

\int_{0}^{\frac{π}{2}} sin^{10} (x) d x

\frac{\partial}{\partial y} (- 4 x y + x^{4} + y^{4})

x \to 0 + lim ((sin (x))^{2 x})

\int_{1}^{3} ln (x) d x

\frac{\partial}{\partial x} (e^{- a x})

What is the derivative of 3x^2+6x ?
The derivative of 3x^2+6x is 6x+6
What is the first derivative of 3x^2+6x ?
The first derivative of 3x^2+6x is 6x+6