What is the derivative of x^2+y^2-25 ?

The derivative of x^2+y^2-25 is 2x+2y(dy)/(dx)

What is the first derivative of x^2+y^2-25 ?

The first derivative of x^2+y^2-25 is 2x+2y(dy)/(dx)

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\frac{d}{d x} (x^{2} + y^{2} - 25)

2 x + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} + y^{2} - 25)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2}) - \frac{d}{d x} (25)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d}{d x} (25) = 0

= 2 x + 2 y \frac{d y}{d x} - 0

Simplify

= 2 x + 2 y \frac{d y}{d x}

\frac{\partial}{\partial x} (3 e^{5 x})

y^{^{''}} - 2 y + y = 12 e^{3 t}

n = 0 \sum \infty \frac{1}{2 n + 2}

(2 + x) y^{^{'}} = 9 y

f (x) = 3 x + 55, at x = 3

What is the derivative of x^2+y^2-25 ?
The derivative of x^2+y^2-25 is 2x+2y(dy)/(dx)
What is the first derivative of x^2+y^2-25 ?
The first derivative of x^2+y^2-25 is 2x+2y(dy)/(dx)