What is the integral of (5cos(x)-2sec^2(x)) ?

The integral of (5cos(x)-2sec^2(x)) is 5sin(x)-2tan(x)+C

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integral of (5cos(x)-2sec^2(x))

\int (5 cos (x) - 2 sec^{2} (x)) d x

5 sin (x) - 2 tan (x) + C

Solution steps

\int 5 cos (x) - 2 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 cos (x) d x - \int 2 sec^{2} (x) d x

\int 5 cos (x) d x = 5 sin (x)

\int 2 sec^{2} (x) d x = 2 tan (x)

= 5 sin (x) - 2 tan (x)

Add a constant to the solution

= 5 sin (x) - 2 tan (x) + C

\frac{d}{d v} (ln (u cos (v)))

\int 9 t^{2} d t

\frac{d}{d x} ((\frac{x ^{2} - 1}{x ^{2} + 1})^{2})

\frac{d}{d x} (x^{\frac{y}{z}})

f (x) = (3 x - 1) (5 x + 2)

What is the integral of (5cos(x)-2sec^2(x)) ?
The integral of (5cos(x)-2sec^2(x)) is 5sin(x)-2tan(x)+C