What is the solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0 ?

The solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0 is y=(2sin(x))/(cos(x))+1+(c_{1})/(cos(x))

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(sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{^{'}} = 0

y = \frac{2 sin ( x )}{cos ( x )} + 1 + \frac{c _{1}}{cos ( x )}

Solution steps

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{2 sin ( x )}{cos ( x )} + 1 + \frac{c _{1}}{cos ( x )}

y = \frac{2 sin ( x )}{cos ( x )} + 1 + \frac{c _{1}}{cos ( x )}

\frac{d}{d x} (\frac{e ^{4 x}}{ln ( 6 x )})

\int \frac{2 x}{e ^{x}} d x

\frac{d}{d x} (36 x^{2})

5 y^{^{''}} + 60 y = 0

What is the solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0 ?
The solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0 is y=(2sin(x))/(cos(x))+1+(c_{1})/(cos(x))