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Popular >

derivative of ln(x^2-8x+1)

Solution

derivative of

ln (x^{2} - 8 x + 1)

Solution

\frac{2 x - 8}{x ^{2} - 8 x + 1}

Solution steps

\frac{d}{d x} (ln (x^{2} - 8 x + 1))

Apply the chain rule:

\frac{1}{x ^{2} - 8 x + 1} \frac{d}{d x} (x^{2} - 8 x + 1)

= \frac{1}{x ^{2} - 8 x + 1} \frac{d}{d x} (x^{2} - 8 x + 1)

\frac{d}{d x} (x^{2} - 8 x + 1) = 2 x - 8

= \frac{1}{x ^{2} - 8 x + 1} (2 x - 8)

Simplify

\frac{1}{x ^{2} - 8 x + 1} (2 x - 8) : \frac{2 x - 8}{x ^{2} - 8 x + 1}

= \frac{2 x - 8}{x ^{2} - 8 x + 1}

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\int 5 x^{2} - 4 d x

Frequently Asked Questions (FAQ)

What is the derivative of ln(x^2-8x+1) ?
The derivative of ln(x^2-8x+1) is (2x-8)/(x^2-8x+1)
What is the first derivative of ln(x^2-8x+1) ?
The first derivative of ln(x^2-8x+1) is (2x-8)/(x^2-8x+1)