What is the tangent of y=7x-6sqrt(x),(1,1) ?

The tangent of y=7x-6sqrt(x),(1,1) is y=4x-3

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tangent of y=7x-6sqrt(x),(1,1)

tangent of

y = 7 x - 6 x, (1, 1)

y = 4 x - 3

Solution steps

Find the slope of

y = 7 x - 6 x : \frac{d y}{d x} = 7 - \frac{3}{x}

Compute the slope of

y = 7 x - 6 x

(1, 1) : m = 4

Find the line with slope m=

4

and passing through

(1, 1) : y = 4 x - 3

y = 4 x - 3

y^{^{''}} + 9 y^{^{'}} - 10 y = 0

\frac{d y}{d x} = 2 + y - 2 x + 3

\int \frac{x ^{3}}{( x ^{2} + 16 ) ^{3}} d x

\int \frac{2 x + 7}{x ^{2} + 2 x + 5} d x

(- x y^{2} - y) d x + (- x^{2} y - x) d y = 0

What is the tangent of y=7x-6sqrt(x),(1,1) ?
The tangent of y=7x-6sqrt(x),(1,1) is y=4x-3