What is the derivative of 9e^{-4x} ?

The derivative of 9e^{-4x} is -36e^{-4x}

What is the first derivative of 9e^{-4x} ?

The first derivative of 9e^{-4x} is -36e^{-4x}

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\frac{d}{d x} (9 e^{- 4 x})

- 36 e^{- 4 x}

Solution steps

\frac{d}{d x} (9 e^{- 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{d}{d x} (- 4 x)

= e^{- 4 x} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= 9 e^{- 4 x} (- 4)

Simplify

= - 36 e^{- 4 x}

y^{3} \frac{d y}{d x} + x^{3} = 0

\frac{\partial}{\partial y} (x^{2} - 4 x y - 2 y^{2})

\int (3 x^{2} - 6 x + 3) d x

\int_{0}^{\frac{1}{4}} 5 arcsin (4 x) d x

\int \frac{6 x ^{3} + 5 x ^{2} - 47 x - 36}{x ^{2} - 9} d x

What is the derivative of 9e^{-4x} ?
The derivative of 9e^{-4x} is -36e^{-4x}
What is the first derivative of 9e^{-4x} ?
The first derivative of 9e^{-4x} is -36e^{-4x}