What is the derivative of (\sqrt[3]{x}/(x^2)) ?

The derivative of (\sqrt[3]{x}/(x^2)) is -5/(3x^{8/3)}

What is the first derivative of (\sqrt[3]{x}/(x^2)) ?

The first derivative of (\sqrt[3]{x}/(x^2)) is -5/(3x^{8/3)}

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- \frac{5}{3 x ^{\frac{8}{3}}}

Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

Simplify

= - \frac{5}{3 x ^{\frac{8}{3}}}

\int x^{2} e^{- \frac{x}{4}} d x

\frac{d}{d x} (cos^{2} (8 x))

(5 x + 3)^{\frac{1}{5}}

f (x) = - \frac{3}{x ^{2}}

\int 14 cos (x) d x

What is the derivative of (\sqrt[3]{x}/(x^2)) ?
The derivative of (\sqrt[3]{x}/(x^2)) is -5/(3x^{8/3)}
What is the first derivative of (\sqrt[3]{x}/(x^2)) ?
The first derivative of (\sqrt[3]{x}/(x^2)) is -5/(3x^{8/3)}