What is the derivative of y=108-90e^{-0.4t} ?

The derivative of y=108-90e^{-0.4t} is 36e^{-0.4t}

What is the first derivative of y=108-90e^{-0.4t} ?

The first derivative of y=108-90e^{-0.4t} is 36e^{-0.4t}

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derivative of

y = 108 - 90 e^{- 0.4 t}

36 e^{- 0.4 t}

Solution steps

\frac{d}{d t} (108 - 90 e^{- 0.4 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (108) - \frac{d}{d t} (90 e^{- 0.4 t})

\frac{d}{d t} (108) = 0

\frac{d}{d t} (90 e^{- 0.4 t}) = - 36 e^{- 0.4 t}

= 0 - (- 36 e^{- 0.4 t})

Simplify

= 36 e^{- 0.4 t}

f (x) = x^{2} e^{x} - 2 x e^{x} + 8 e^{x}

h \to 0 lim (\frac{( 1 + h ) - ( 1 )}{h})

\frac{d y}{d x} = - y - 8

g (x) = 7 e^{x} x

sin (x^{2} + 4)

What is the derivative of y=108-90e^{-0.4t} ?
The derivative of y=108-90e^{-0.4t} is 36e^{-0.4t}
What is the first derivative of y=108-90e^{-0.4t} ?
The first derivative of y=108-90e^{-0.4t} is 36e^{-0.4t}