What is (\partial)/(\partial x)(y^2-3x^3) ?

The answer to (\partial)/(\partial x)(y^2-3x^3) is -9x^2

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(\partial)/(\partial x)(y^2-3x^3)

\frac{\partial}{\partial x} (y^{2} - 3 x^{3})

- 9 x^{2}

Solution steps

\frac{\partial}{\partial x} (y^{2} - 3 x^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (3 x^{3})

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (3 x^{3}) = 9 x^{2}

= 0 - 9 x^{2}

Simplify

= - 9 x^{2}

4 + t^{6}

f (x) = - 5 x

y^{^{'''}} - 7 y^{^{'}} + 6 y = e^{3 x}

\frac{d}{d x} (1 - x^{2} + y^{2})

\int \frac{x + 1}{3 x + 2} d x

What is (\partial)/(\partial x)(y^2-3x^3) ?
The answer to (\partial)/(\partial x)(y^2-3x^3) is -9x^2