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Popular >

y^'=0.1y(10-y)

Solution

y^{^{'}} = 0.1 y (10 - y)

Solution

y = \frac{10}{- 10 e ^{- t - c_{1}} + 1}

Solution steps

y^{'} (t) = 0.1 y (10 - y)

Solve Bernoulli ODE:

y = \frac{10}{- 10 e ^{- t - c_{1}} + 1}

y = \frac{10}{- 10 e ^{- t - c_{1}} + 1}

Popular Examples

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n = 6 \sum \infty \frac{5}{n ^{2} - 25}

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\frac{d}{d x} ((x^{2}) (y^{2} - 9))

derivative of sqrt(x/3)derivative of

\frac{x}{3}

Frequently Asked Questions (FAQ)

What is the solution for y^'=0.1y(10-y) ?
The solution for y^'=0.1y(10-y) is y=(10)/(-10e^{-t-c_{1)}+1}