What is the derivative of x^3+3x^2-6x-8 ?

The derivative of x^3+3x^2-6x-8 is 3x^2+6x-6

What is the first derivative of x^3+3x^2-6x-8 ?

The first derivative of x^3+3x^2-6x-8 is 3x^2+6x-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{3} + 3 x^{2} - 6 x - 8)

3 x^{2} + 6 x - 6

Solution steps

\frac{d}{d x} (x^{3} + 3 x^{2} - 6 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (6 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (8) = 0

= 3 x^{2} + 6 x - 6 - 0

Simplify

= 3 x^{2} + 6 x - 6

\int \frac{( arctan ( x ) ) ^{7}}{x ^{2} + 1} d x

f (x) = 3 x^{2} e^{x} + e^{x} (x^{3} + 3)

\int 4 x^{2} x + 9 d x

\int cot (\frac{θ}{7}) d θ

What is the derivative of x^3+3x^2-6x-8 ?
The derivative of x^3+3x^2-6x-8 is 3x^2+6x-6
What is the first derivative of x^3+3x^2-6x-8 ?
The first derivative of x^3+3x^2-6x-8 is 3x^2+6x-6