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Popular >

derivative of y=e^{-x}ln(x)

Solution

derivative of

y = e^{- x} ln (x)

Solution

- e^{- x} ln (x) + \frac{e ^{- x}}{x}

Solution steps

\frac{d}{d x} (e^{- x} ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{- x}, g = ln (x)

= \frac{d}{d x} (e^{- x}) ln (x) + \frac{d}{d x} (ln (x)) e^{- x}

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= (- e^{- x}) ln (x) + \frac{1}{x} e^{- x}

Simplify

(- e^{- x}) ln (x) + \frac{1}{x} e^{- x} : - e^{- x} ln (x) + \frac{e ^{- x}}{x}

= - e^{- x} ln (x) + \frac{e ^{- x}}{x}

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Frequently Asked Questions (FAQ)

What is the derivative of y=e^{-x}ln(x) ?
The derivative of y=e^{-x}ln(x) is -e^{-x}ln(x)+(e^{-x})/x
What is the first derivative of y=e^{-x}ln(x) ?
The first derivative of y=e^{-x}ln(x) is -e^{-x}ln(x)+(e^{-x})/x