What is the derivative of f(x)=((x-2)^5)/(16) ?

The derivative of f(x)=((x-2)^5)/(16) is (5(x-2)^4)/(16)

What is the first derivative of f(x)=((x-2)^5)/(16) ?

The first derivative of f(x)=((x-2)^5)/(16) is (5(x-2)^4)/(16)

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derivative of

f (x) = \frac{( x - 2 ) ^{5}}{16}

\frac{5 ( x - 2 ) ^{4}}{16}

Solution steps

\frac{d}{d x} (\frac{( x - 2 ) ^{5}}{16})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{16} \frac{d}{d x} ((x - 2)^{5})

Apply the chain rule:

5 (x - 2)^{4} \frac{d}{d x} (x - 2)

= 5 (x - 2)^{4} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= \frac{1}{16} \cdot 5 (x - 2)^{4} \cdot 1

Simplify

\frac{1}{16} \cdot 5 (x - 2)^{4} \cdot 1 : \frac{5 ( x - 2 ) ^{4}}{16}

= \frac{5 ( x - 2 ) ^{4}}{16}

x \to \infty lim (\frac{2 x ^{3} - 5 x + 4}{x ^{2} + 3 x - 4})

x cos (x)

\int \frac{9}{x ^{2} - 6 x + 18} d x

\frac{0.6}{s}

\int_{- 1}^{0} - 1 d x

What is the derivative of f(x)=((x-2)^5)/(16) ?
The derivative of f(x)=((x-2)^5)/(16) is (5(x-2)^4)/(16)
What is the first derivative of f(x)=((x-2)^5)/(16) ?
The first derivative of f(x)=((x-2)^5)/(16) is (5(x-2)^4)/(16)