What is the integral of (8+5x)/(1+x^2) ?

The integral of (8+5x)/(1+x^2) is 8arctan(x)+5/2 ln|1+x^2|+C

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integral of (8+5x)/(1+x^2)

\int \frac{8 + 5 x}{1 + x ^{2}} d x

8 arctan (x) + \frac{5}{2} ln 1 + x^{2} + C

Solution steps

\int \frac{8 + 5 x}{1 + x ^{2}} d x

Expand

\frac{8 + 5 x}{1 + x ^{2}} : \frac{8}{1 + x ^{2}} + \frac{5 x}{1 + x ^{2}}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{8}{1 + x ^{2}} d x + \int \frac{5 x}{1 + x ^{2}} d x

\int \frac{8}{1 + x ^{2}} d x = 8 arctan (x)

\int \frac{5 x}{1 + x ^{2}} d x = \frac{5}{2} ln 1 + x^{2}

= 8 arctan (x) + \frac{5}{2} ln 1 + x^{2}

Add a constant to the solution

= 8 arctan (x) + \frac{5}{2} ln 1 + x^{2} + C

x \to - 10 - lim (\frac{1}{x + 10})

\frac{d}{d x} (tan (4 x^{5}) sec (2 x^{3}))

\int π^{2} - x^{2} d x

\int \frac{8}{1 + 8 x} d x

\frac{d}{d x} ((3 x^{2})^{2 x} \cdot (x^{2} + 2 x)^{2})

What is the integral of (8+5x)/(1+x^2) ?
The integral of (8+5x)/(1+x^2) is 8arctan(x)+5/2 ln|1+x^2|+C