What is (\partial)/(\partial x)(e^x+yz) ?

The answer to (\partial)/(\partial x)(e^x+yz) is e^x

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(\partial)/(\partial x)(e^x+yz)

\frac{\partial}{\partial x} (e^{x} + yz)

e^{x}

Solution steps

\frac{\partial}{\partial x} (e^{x} + yz)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x}) + \frac{\partial}{\partial x} (yz)

\frac{\partial}{\partial x} (e^{x}) = e^{x}

\frac{\partial}{\partial x} (yz) = 0

= e^{x} + 0

Simplify

= e^{x}

3 x y^{^{'}} - y (x + 1) + 7 y^{4} = 0

\frac{d y}{d x}, x^{2} + y^{2} = 24

cos^{2} (t)

tan^{6} (x)

h \to 0 lim (cos (\frac{3}{h}))

What is (\partial)/(\partial x)(e^x+yz) ?
The answer to (\partial)/(\partial x)(e^x+yz) is e^x