What is the derivative of ln(2)+ln(x) ?

The derivative of ln(2)+ln(x) is 1/x

What is the first derivative of ln(2)+ln(x) ?

The first derivative of ln(2)+ln(x) is 1/x

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derivative of

ln (2) + ln (x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (2) + ln (x))

Simplify

ln (2) + ln (x) : ln (2 x)

= \frac{d}{d x} (ln (2 x))

Apply the chain rule:

\frac{1}{2 x} \frac{d}{d x} (2 x)

= \frac{1}{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= \frac{1}{2 x} \cdot 2

Simplify

\frac{1}{2 x} \cdot 2 : \frac{1}{x}

= \frac{1}{x}

y = \frac{e ^{6 x}}{e ^{6 x} + 3}

\frac{\partial}{\partial x} (e^{- 3 y} cos (π x))

6 y^{^{''}} - y^{^{'}} - 2 y = 0

\int \frac{1 + sin ( x )}{1 + cos ( x )} d x

\frac{\partial}{\partial x} (\frac{( y - 3 x )}{z})

What is the derivative of ln(2)+ln(x) ?
The derivative of ln(2)+ln(x) is 1/x
What is the first derivative of ln(2)+ln(x) ?
The first derivative of ln(2)+ln(x) is 1/x