What is the integral of 1/((1+2x)^2) ?

The integral of 1/((1+2x)^2) is -1/(2(1+2x))+C

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integral of 1/((1+2x)^2)

\int \frac{1}{( 1 + 2 x ) ^{2}} d x

- \frac{1}{2 ( 1 + 2 x )} + C

Solution steps

\int \frac{1}{( 1 + 2 x ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{2 u ^{2}} d u

= \int \frac{1}{2 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= \frac{1}{2} (- \frac{1}{u})

Substitute back

u = 1 + 2 x

= \frac{1}{2} (- \frac{1}{1 + 2 x})

Simplify

\frac{1}{2} (- \frac{1}{1 + 2 x}) : - \frac{1}{2 ( 1 + 2 x )}

= - \frac{1}{2 ( 1 + 2 x )}

Add a constant to the solution

= - \frac{1}{2 ( 1 + 2 x )} + C

\int 1 + e^{x^{2}} d x

\frac{\partial}{\partial y} (e^{x^{2} + y^{2}} \cdot 2 y)

\int \frac{x ^{\frac{1}{3}} - 3}{x ^{\frac{2}{3}}} d x

\int_{0}^{2} 1 + 4 x^{2} d x

q^{^{'}} + \frac{q}{20 + t} = 1, q (0) = 5

What is the integral of 1/((1+2x)^2) ?
The integral of 1/((1+2x)^2) is -1/(2(1+2x))+C