What is the integral of (sec^2(x)-tan^2(x)) ?

The integral of (sec^2(x)-tan^2(x)) is x+C

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integral of (sec^2(x)-tan^2(x))

\int (sec^{2} (x) - tan^{2} (x)) d x

x + C

Solution steps

\int sec^{2} (x) - tan^{2} (x) d x

Rewrite using trig identities

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

\int_{- 7}^{7} (49 - x^{2}) d x

\int - 2 x d x

\frac{d}{d x} (\frac{40}{0.01 x ^{2} + 1})

\frac{d}{d x} (e^{n x^{2}})

x^{^{'}} = x^{2} + x

What is the integral of (sec^2(x)-tan^2(x)) ?
The integral of (sec^2(x)-tan^2(x)) is x+C