What is the tangent of y= 1/(x+1),(1, 1/2) ?

The tangent of y= 1/(x+1),(1, 1/2) is y=-1/4 x+3/4

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tangent of y= 1/(x+1),(1, 1/2)

tangent of

y = \frac{1}{x + 1}, (1, \frac{1}{2})

y = - \frac{1}{4} x + \frac{3}{4}

Solution steps

Find the slope of

y = \frac{1}{x + 1} : \frac{d y}{d x} = - \frac{1}{( x + 1 ) ^{2}}

Compute the slope of

y = \frac{1}{x + 1}

(1, \frac{1}{2}) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(1, \frac{1}{2}) : y = - \frac{1}{4} x + \frac{3}{4}

y = - \frac{1}{4} x + \frac{3}{4}

(1 + t)^{3}

\int 2 e^{2 t} d t

\frac{d}{d x} ((x^{2} + 2 x)^{4} (x^{2} + 3 x^{2} + 7)^{3})

y = x^{2} - 5 x + 3, (2, - 3)

\int x \cdot x^{2} - 1 d x

What is the tangent of y= 1/(x+1),(1, 1/2) ?
The tangent of y= 1/(x+1),(1, 1/2) is y=-1/4 x+3/4