What is the sum from n=1 to infinity of 1/(n^{-10)} ?

The sum from n=1 to infinity of 1/(n^{-10)} is diverges

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sum from n=1 to infinity of 1/(n^{-10)}

n = 1 \sum \infty \frac{1}{n ^{- 10}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{- 10}}

Simplify

\frac{1}{n ^{- 10}} : n^{10}

= n = 1 \sum \infty n^{10}

Apply Series Divergence Test:

diverges

= diverges

y = x^{2} + x + 3

\frac{1}{x}, at x = 9

\frac{d}{d x} (x (x - 1))

x \to 0 + lim (tan^{x} (5 x))

x y^{^{'}} + (1 - x) y = 1

What is the sum from n=1 to infinity of 1/(n^{-10)} ?
The sum from n=1 to infinity of 1/(n^{-10)} is diverges