What is the tangent of (18)/x ?

The tangent of (18)/x is y=-(18)/(a_{0)^2}x+(36)/(a_{0)}

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tangent of (18)/x

tangent of

\frac{18}{x}

y = - \frac{18}{a _{0}^{2}} x + \frac{36}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{18}{a _{0}})

Find the slope of

y = \frac{18}{x} : \frac{d y}{d x} = - \frac{18}{x ^{2}}

Compute the slope of

y = \frac{18}{x}

x = a_{0} : m = - \frac{18}{a _{0}^{2}}

Find the line with slope m=

- \frac{18}{a _{0}^{2}}

and passing through

(a_{0}, \frac{18}{a _{0}}) : y = - \frac{18}{a _{0}^{2}} x + \frac{36}{a _{0}}

y = - \frac{18}{a _{0}^{2}} x + \frac{36}{a _{0}}

\int t^{- 4} d t

\frac{d}{d x} (\frac{x ^{2} + x - 2}{x ^{3} + 6})

y, ln (x y 9) = x y

y = \frac{1}{2} x^{3} + 2, y = x + 1, x = 0, x = 2

x \to \infty lim (1 + \frac{2 ^{x + 1}}{2 ^{x} - 1})

What is the tangent of (18)/x ?
The tangent of (18)/x is y=-(18)/(a_{0)^2}x+(36)/(a_{0)}