What is the solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=8 ?

The solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=8 is y= 7/((x^2+1)^{3/2)}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=8

(x^{2} + 1) (\frac{d y}{d x}) + 3 x (y - 1) = 0, y (0) = 8

y = \frac{7}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

(x^{2} + 1) (\frac{d y}{d x}) + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{7}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{7}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

x \to - 3 lim (x x + 3)

\frac{\partial}{\partial z} (6 z e^{x yz})

\int \frac{5 + 2 tan ( x )}{cos ^{2} ( x )} d x

\int - x^{2} + 4 x + 5 d x

f (x) = - 8 x

What is the solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=8 ?
The solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=8 is y= 7/((x^2+1)^{3/2)}+1