What is the integral of x^{3/4}+6 ?

The integral of x^{3/4}+6 is 4/7 x^{7/4}+6x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^{3/4}+6

\int x^{\frac{3}{4}} + 6 d x

\frac{4}{7} x^{\frac{7}{4}} + 6 x + C

Solution steps

\int x^{\frac{3}{4}} + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{4}} d x + \int 6 d x

\int x^{\frac{3}{4}} d x = \frac{4}{7} x^{\frac{7}{4}}

\int 6 d x = 6 x

= \frac{4}{7} x^{\frac{7}{4}} + 6 x

Add a constant to the solution

= \frac{4}{7} x^{\frac{7}{4}} + 6 x + C

y^{^{'''}} - 6 y^{^{''}} - 7 y^{^{'}} = 0

\int t^{3} d t

\int (\frac{( x ^{3} - 3 x ^{2} + 3 )}{( x - 3 )}) d x

x \to 0 lim (\frac{( - 6 + x ) ^{2} - 36}{x})

\frac{d}{d x} (- x^{3} + 2 x^{2} + 11 x + a)

What is the integral of x^{3/4}+6 ?
The integral of x^{3/4}+6 is 4/7 x^{7/4}+6x+C