What is the tangent of f(x)= 4/x ,(-2,-2) ?

The tangent of f(x)= 4/x ,(-2,-2) is y=-x-4

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tangent of f(x)= 4/x ,(-2,-2)

tangent of

f (x) = \frac{4}{x}, (- 2, - 2)

y = - x - 4

Solution steps

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{4}{x ^{2}}

Compute the slope of

f (x) = \frac{4}{x}

(- 2, - 2) : m = - 1

Find the line with slope m=

- 1

and passing through

(- 2, - 2) : y = - x - 4

y = - x - 4

\frac{d y}{d x} = 1 + e^{y - x + 3}

\int (\frac{x + 8}{x}) d x

\int_{- 3}^{3} (15 - x^{2}) - (x^{2} - 3) d x

\int \frac{- 4}{cos ( x ) - 1} d x

6 (ln (y)) y^{^{'}} - x^{3} y = 0

What is the tangent of f(x)= 4/x ,(-2,-2) ?
The tangent of f(x)= 4/x ,(-2,-2) is y=-x-4