What is the derivative of x^3+3x-6 ?

The derivative of x^3+3x-6 is 3x^2+3

What is the first derivative of x^3+3x-6 ?

The first derivative of x^3+3x-6 is 3x^2+3

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\frac{d}{d x} (x^{3} + 3 x - 6)

3 x^{2} + 3

Solution steps

\frac{d}{d x} (x^{3} + 3 x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (6)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (6) = 0

= 3 x^{2} + 3 - 0

Simplify

= 3 x^{2} + 3

\int \frac{7 - 98 x}{36 - 49 x ^{2}} d x

x = y^{2}, x = y^{3}

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\int ∣ 1 - x ∣ d x

What is the derivative of x^3+3x-6 ?
The derivative of x^3+3x-6 is 3x^2+3
What is the first derivative of x^3+3x-6 ?
The first derivative of x^3+3x-6 is 3x^2+3