What is the integral from 1 to 2 of x^3 ?

The integral from 1 to 2 of x^3 is 15/4

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integral from 1 to 2 of x^3

\int_{1}^{2} x^{3} d x

\frac{15}{4}

Decimal Notation

3.75

Solution steps

\int_{1}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{2}

= [\frac{x ^{4}}{4}]_{1}^{2}

Compute the boundaries:

\frac{15}{4}

= \frac{15}{4}

\frac{d}{d x} (\frac{x - 9}{x + 9})

(\frac{1}{2}, 1), (3 \frac{3}{4}, 3 \frac{1}{2})

y d x + (x + \frac{2}{y}) d y = 0

\int_{1}^{4} 1 + 9 x d x

What is the integral from 1 to 2 of x^3 ?
The integral from 1 to 2 of x^3 is 15/4